Как разархивировать отдельный файл из zip архива в android?

 1
 2
 3
 4
 5
 6
 7
 8
 9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36

import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;

public class ZipUtils {

    public static void extractFileFromZip(File zipFile, String filePath, String destinationPath) throws IOException {
        byte[] buffer = new byte[4096];
        
        try (ZipInputStream zis = new ZipInputStream(new FileInputStream(zipFile))) {
            ZipEntry zipEntry;
            while ((zipEntry = zis.getNextEntry()) != null) {
                if (!zipEntry.isDirectory() && zipEntry.getName().equals(filePath)) {
                    File outputFile = new File(destinationPath);
                    
                    // Create any necessary directories
                    outputFile.getParentFile().mkdirs();
                    
                    // Extract the file
                    try (BufferedOutputStream bos = new BufferedOutputStream(new FileOutputStream(outputFile))) {
                        int bytesRead;
                        while ((bytesRead = zis.read(buffer)) != -1) {
                            bos.write(buffer, 0, bytesRead);
                        }
                    }
                    
                    break;
                }
            }
        }
    }
}

1
2
3
4
5

try {
    ZipUtils.extractFileFromZip(new File("путь_к_zip_архиву"), "путь_к_архивируемому_файлу", "путь_назначения");
} catch (IOException e) {
    e.printStackTrace();
}